Sia h (x) = 6x ^ 5-5x ^ 4 + 4x ^ 3-3x ^ 2-2x + x + 7 and m (x) = x ^ 2-1, come trovi il quoziente h (x) e m (x)?

Sia h (x) = 6x ^ 5-5x ^ 4 + 4x ^ 3-3x ^ 2-2x + x + 7 and m (x) = x ^ 2-1, come trovi il quoziente h (x) e m (x)?
Anonim

Risposta:

# -6x ^ 5 + 5x ^ 4-3x ^ 3 + 2x ^ 2 + x-7 #

Spiegazione:

#h (x) = 6x ^ 5-5x ^ 4 + 4x ^ 3-3x ^ 2-2x + x + 7 #

#m (x) = x ^ 2-1 #

perciò, #h (x) = (6x ^ 5-5x ^ 4 + 4x ^ 3-3x ^ 2-2x + x + 7) / (x ^ 2-1) #

=# - (6x ^ 5-5x ^ 4 + 3x ^ 3-2x ^ 2-x + 1) #

=# -6x ^ 5 + 5x ^ 4-3x ^ 3 + 2x ^ 2 + x + 1 #

semplificare # (- 2x + x) # e # (- 3x ^ 2 e x ^ 2) #