Come dividi (-6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3)?

Come dividi (-6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3)?
Anonim

Risposta:

#color (blu) ((- 6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3) = - 6x ^ 2-3x + 16 + (5x-55) / (x ^ 2 + 3)) #

Spiegazione:

# (- 6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3) #

Il metodo della divisione lunga:

# "" "" "" "" "" "" sottolineatura (-6x ^ 2-3x + 16 "" "" "" "" "" "" "" "" "" ") #

# X ^ 2 + 0 * x + 3 | ~ -6x ^ 4-3x ^ 3-2x ^ 2-4x-7 #

# "" "" "" "" "" "" sottolineatura (-6x ^ 4 + 0 * x ^ 3-18x ^ 2 "" "" "") #

# "" "" "" "" "" "" "" "" "-3x ^ 3 + 16x ^ 2-4x-7 #

# "" "" "" "" "" "" "" "" "sottolineatura (-3x ^ 3 + 0 * x ^ 2-9x) #

# "" "" "" "" "" "" "" "" "" "" "" 16x ^ 2 + 5x-7 #

# "" "" "" "" "" "" "" "" "" "" "" sottolineatura (16x ^ 2 + 0 * x + 48) #

# "" "" "" "" "" "" "" "" "" "" "" "" "" + 5x-55 larr #Resto

La risposta

#color (blu) ((- 6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3) = - 6x ^ 2-3x + 16 + (5x-55) / (x ^ 2 + 3)) #