Risolvi per x dove pi <= x <= 2pi? Tan ^ 2 x + 2 sqrt (3) tan x + 3 = 0

Risposta:

# X = NPI + (2pi) / 3 # dove #n in ZZ #

Spiegazione:

# Rarrtan ^ 2x + 2sqrt3tanx + 3 = 0 #

#rarr (tanx) ^ 2 + 2 * * tanx sqrt3 + (sqrt3) ^ 2 = 0 #

#rarr (tanx + sqrt3) ^ 2 = 0 #

# Rarrtanx = -sqrt3 = tan ((2pi) / 3) #

# Rarrx = NPI + (2pi) / 3 # dove #n in ZZ #